Clone an undirected graph. Each node in the graph contains a
label and a list of its neighbors.OJ's undirected graph serialization:
Nodes are labeled uniquely.
We use # as a separator for each node, and , as a separator for node label and each neighbor of the node.
As an example, consider the serialized graph
{0,1,2#1,2#2,2}.
The graph has a total of three nodes, and therefore contains three parts as separated by
#.- First node is labeled as
0. Connect node0to both nodes1and2. - Second node is labeled as
1. Connect node1to node2. - Third node is labeled as
2. Connect node2to node2(itself), thus forming a self-cycle.
Visually, the graph looks like the following:
1
/ \
/ \
0 --- 2
/ \
\_/
这道题是一个DFS, 借助queue做DFS遍历,借助hashmap记录那些copy的node已经建立过。
/**
* Definition for undirected graph.
* class UndirectedGraphNode {
* int label;
* List neighbors;
* UndirectedGraphNode(int x) { label = x; neighbors = new ArrayList(); }
* };
*/
public class Solution {
public UndirectedGraphNode cloneGraph(UndirectedGraphNode node) {
if(node==null) return null;
//create a linkedlist for bfs
LinkedList queue = new LinkedList();
//create hashmap for clone
HashMap map = new HashMap();
queue.add(node);
UndirectedGraphNode newHead = new UndirectedGraphNode(node.label);
map.put(node, newHead);
while(!queue.isEmpty()){
UndirectedGraphNode cur = queue.remove();
List curNeighbors = cur.neighbors;
for(UndirectedGraphNode n : curNeighbors){
if(map.containsKey(n))
map.get(cur).neighbors.add(map.get(n));//map中有n,则把n的copy加入到cur的copy的neighbor list里即可
else{
queue.add(n);//map中没有,则queue中也没有。
UndirectedGraphNode newNode = new UndirectedGraphNode(n.label);
map.put(n, newNode);
map.get(cur).neighbors.add(newNode);
}
}
}
return newHead;
}
}
No comments:
Post a Comment